Is most wood surfaced on all sides at the mill

The density of the wooden cube is   [tex]\delta= 0.4 \, \frac{g}{cm^3}[/tex]

Explanation:

Recall that the weight of the entire piece of wood that is floating must equal the weight of the displaced water in the case we have an object under flotation.

At the same time. we have a relationship between Volume (V), Weight (w) and density [tex](\delta)[/tex]  given by the formula:

[tex]w=\delta\,*\,V[/tex]

Since both weights must be the same, we can write the following equation:

[tex]w_{wood} = w_{water}\\\delta *\,(5\,\,cm)^3= (\frac{1\,g}{cm^3} )\,(2\,*5^2) cm^3\\\delta= \frac{2}{5} \, \frac{g}{cm^3} \\\delta= 0.4 \, \frac{g}{cm^3}[/tex]

For 10 feet and 6 inches,           

12 inches = 1 foot, therefore 6 inches = 6/12 foot = 0.5 foot

10 feet 6 inches = 10 + 0.5 = 10.5 feet

7 feet required 3 pints

1 foot would have required (3/7) pints

10.5 feet will then require:      (3/7)*10.5 = 4.5 pints.

Therefore 10 feet and 6 inches will require 4.5 pints.