In the paper airplane shown abcd is congruent to efgh angle b= angle bcd= 90 and angle bad = 143 find angle feh

6 answers
Question:

In the paper airplane shown abcd is congruent to efgh angle b= angle bcd= 90 and angle bad = 143 find angle feh

Answers

ABCD ~ EFGH

Corresponding sides and corresponding angles are equal.

[tex]\angle{FEH}=\angle{BAD}=143^o[/tex]

[tex]In the paper airplane shown abcd is congruent to efgh angle b= angle bcd= 90 and angle bad = 143 fi[/tex]

Angle FEH = 143.

Step-by-step explanation:

Given : in the paper airplane shown ABCD is congruent to EFGH ... angle B= angle BCD= 90 and angle BAD = 143.

To find : angle FEH.

Solution : We have given quadrilateral ABCD is congruent to EFGH.

Shapes of quadrilateral ABCD and  EFGH is trapezoid.

By congruent rule : side AB ≅ EF, BC≅FG, CD≅GH, DA≅HE and all corresponding angles are equal.

By given statement angle B = angle BCD = 90 and angle BAD = 143

We can see by congruent rule angle BAD ≅ angle FEH = 143.

Therefore, angle FEH = 143.

3. the answer is B.
4. the answer is A.
5. the answer is B.
6. the answer is D.
7. ??
8. ??

3) D: The vertex, in this case N (as the middle point) needs to be in the middle of the name.

4) C: These triangles are reflection of each other, if you would place them in front of a mirror, this would be the only one true.

5) A: According to the picture, the angles are the same, so what will be missing is to know if the hypotenuse is the same, as we already know that one side is the same (perpendicular one), therefore we already have S(side), A (angle), missing side (S) for it to be solved by SAS.

6) A: ASA postulate says that you need one angle (A1), the side between A1 and A2, and a second angle (A2), which corresponds to tha description.

7) missing the picture

8) B: 65. Two of the angles are 90 and the other one is 125. Within any quadrilateral the sum of angles must be 360. Therefore m=360-90-90-125=65.

Step-by-step explanation:

I think the answer  might be D hope this helps

The answer is d because angle b is a 90 degree angle (because it is as corner of paper); angle c is also 90 (it's given); and angle a is 143 (also given). You add all three up and get 323. Subtract 323 from 360 (because 360 is how many degrees that are in a quadrilateral) and the answer is 37

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