In a random sample of 11 residents of the state of New York, the mean waste recycled per person per

3 answers
Question:

In a random sample of 11 residents of the state of New York, the mean waste recycled per person per day was 2.9 pounds with a standard deviation of 0.98 pounds. Determine the 80% confidence interval for the mean waste recycled per person per day for the population of New York. Assume the population is approximately normal. Step 1 of 2 : Find the critical value that should be used in constructing the confidence interval. Round your answer to three decimal places.

Answers

80% confidence interval for the mean waste recycled per person per day for the population of New York is [2.495 , 3.305].

Step-by-step explanation:

We are given that a random sample of 11 residents of the state of New York, the mean waste recycled per person per day was 2.9 pounds with a standard deviation of 0.98 pounds.

Firstly, the pivotal quantity for 80% confidence interval for the true mean waste recycled per person per day for the population of New York is given by;

         P.Q. = [tex]\frac{\bar X - \mu}{\frac{s}{\sqrt{n} } }[/tex] ~ [tex]t_n_-_1[/tex]

where, [tex]\bar X[/tex] = sample mean waste recycled per person per day = 2.9 pounds

             s = sample standard deviation = 0.98 pounds

             n = sample of residents = 11

             [tex]\mu[/tex] = true mean waste recycled per person per day

Here for constructing 80% confidence interval we have used t statistics because we don't know about population standard deviation.

So, 80% confidence interval for the true mean, [tex]\mu[/tex] is ;

P(-1.372 < [tex]t_1_0[/tex] < 1.372) = 0.80  {As the critical value of t at 10 degree of

                                                 freedom are -1.372 & 1.372 with P = 10%}

P(-1.372 < [tex]\frac{\bar X - \mu}{\frac{s}{\sqrt{n} } }[/tex] < 1.372) = 0.80

P( [tex]-1.372 \times {\frac{s}{\sqrt{n} } }[/tex] < [tex]{\bar X - \mu}[/tex] < [tex]1.372 \times {\frac{s}{\sqrt{n} } }[/tex] ) = 0.80

P( [tex]-\bar X -1.372 \times {\frac{s}{\sqrt{n} }[/tex] < - [tex]\mu[/tex] < [tex]-\bar X +1.372 \times {\frac{s}{\sqrt{n} }[/tex] ) = 0.80

P( [tex]\bar X -1.372 \times {\frac{s}{\sqrt{n} }[/tex] < [tex]\mu[/tex] < [tex]\bar X +1.372 \times {\frac{s}{\sqrt{n} }[/tex] ) = 0.80

80% confidence interval for [tex]\mu[/tex] = [ [tex]\bar X -1.372 \times {\frac{s}{\sqrt{n} }[/tex] , [tex]\bar X +1.372 \times {\frac{s}{\sqrt{n} }[/tex] ]

                                                 = [ [tex]2.9 -1.372 \times {\frac{0.98}{\sqrt{11} }[/tex] , [tex]2.9 -1.372 \times {\frac{0.98}{\sqrt{11} }[/tex] ]

                                                 = [2.495 , 3.305]

Therefore, 80% confidence interval for the mean waste recycled per person per day for the population of New York is [2.495 , 3.305].

seems like d

step-by-step explanation:

the reporter's right

step-by-step explanation:

1/4 = .25 / 25%

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