If the tank is designed to withstand a pressure of 5 MPaMPa, determine the required minimum wall thickness to the nearest millimeter

hello some aspects of your question is missing below is the missing information

The gas tank is made from A-36 steel and has an inner diameter of 1.50 m.

≈ 22.5 mm

Explanation:

Given data:

Inner diameter = 1.5 m

pressure = 5 MPa

factor of safety = 1.5

Calculate the required minimum wall thickness

maximum-shear-stress theory ( σ allow ) = σγ / FS

                                                  = 250(10)^6 / 1.5  = 166.67 (10^6) Pa

given that |σ| = σ allow  

3.75 (10^6) / t = 166.67 (10^6)

∴ t ( wall thickness ) = 0.0225 m   ≈ 22.5 mm

It would be d because i did like a whole test about this

explanation:  

an electrode is a metal whose surface serves as the location where oxidation-reduction equilibrium is established between the metal and what is in the solution.