If 8.60 grams of methane gas (hint: remember the fuel for the bunsen burner) is in a 2.00 l container

3 answers
Question:

If 8.60 grams of methane gas (hint: remember the fuel for the bunsen burner) is in a 2.00 l container at 66oc, what is the pressure in the container?

Answers

Data:

Gas: methane = CH4

V = 2.00 liter

T = 66°C = 66 + 273.15 K = 339.15 K

 Use the ideal gas equation pV = n RT

R = 0.082 atm*liter / K*mol

n is the number of moles and is calculated using the molar mass,MM, of CH4.

MM of CH4 = 12.0 g/mol + 4*1 g/mol = 16.0 g / mol

n = mass / MM = 8.60 g / 16.0 g/mol   = 0.5375 mol

Now you can use the formula: pV = nRT => p = nRT / V

p = 0.5375 mol * 0.082 atm*liter / K*mol * 339.15 K / 2.00 liter

p = 7.47 atm

Inot sure what it is i sorry : ((

the correct answer is b. a strong acid completely dissociates to its ions when dissolved in water. [tex]hbr[/tex] completely dissociates to [tex]h^+[/tex] and [tex]br-[/tex] ions. a is incorrect because [tex]h_2s[/tex] does not fully ionize to [tex]h^+[/tex] and [tex]hs^-[/tex] ions and some remain as the compound [tex]h_2s[/tex]. c and d are incorrect because, [tex]li_2o[/tex] and [tex]libr[/tex] do not fall into the category of bronsted lowry acids. a bronsted lowry acid is a proton donor and since both molecules do not have a proton to donate they are not bronsted lowry acids. likewise,   if we use the lewis acid definition, they cannot be acids. a lewis acid is an electron pair acceptor. both [tex]li_2o[/tex] and [tex]libr[/tex] have a complete octet so can not accept any electrons which disqualifies them as acids.

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