If 45.8 grams of mgo are dissolved in 205 grams of water, what is the concentration of the solution
3 answers
Question:
If 45.8 grams of mgo are dissolved in 205 grams of water, what is the concentration of the solution in percent by mass?
Answers
Mass of solute = 45.8 g
Mass of solvent = 205 g
solute / ( solute + solvent )
45.8 / ( 45.8 + 205 )
45.8 / 250.8
= 0.182 x 100 = 18.2% by mass
hope this helps!
percent by mass = mass (MgO) / mass (solution)
mass of solution = 45.8 grams (MgO) + 205 grams (H2O) = 250. grams
mass (MgO) = 45.8 grams
percent by mass = 45.8 grams / 250. grams = 0.1832 = 18.32%
Although it's true that MgO is only very slightly soluble in water, you can consider the mixture a conventional solution for the purposes of this question. The % mass is the mass of MgO divided by the mass of the entire solution:
45.8 / (45.8 + 205) * 100 = 18.3%
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