I need help finding the area pls and ty.

10 answers
Question:

I need help finding the area pls and ty.

[tex]I need help finding the area pls and ty.[/tex]


Answers

28.5 square units
Hope this help

  310.625 ft²

Step-by-step explanation:

Jocelyn's rectangular pool has an area that is the product of its length and width:

  area = L·W = (14.75 ft)(7.5 ft) = 110.625 ft

The community pool is 200 ft² larger, so its area is ...

  community pool area = 110.625 ft² +200 ft² = 310.625 ft²

132

Step-by-step explanation:

Area for a trapezoid:

A=[tex]\frac{a+b}{2}h[/tex]

A=[tex]\frac{7+19}{2}*8[/tex]

A=[tex]\frac{26}{2}*8[/tex]

A=13*8

A=104

Area for a rectangle:

A=lw

A=4*7

A=28

Now you have to add the two areas to get 132.

28.5 units squared

Step-by-step explanation:

8x3 is the bottom rectangle and added 3x3x0.5 cuz it is a triangle. Add the areas and u get 4.5+24 or 28.5 units squared

33 (units)

Step-by-step explanation:

We can divide this into three parts. The rectangle, and the two triangles. Find the area of the rectangle (l*w, so 4*6, which is 24) and then find the area of the triangles (b*h/2, so 3*3/2, which is 4.5). Since there are two triangles, we can multiply the area of one triangle by two (4.5*2=9). Add up the area of each part (24 for the rectangle, 9 for the added triangles) and you get (24+9=33), which is your answer!

[tex]A_{pentagon}=5( 13252.5)=66262.5ft^{2}[/tex]

Step-by-step explanation:

If the pentagon is inscribed inside a circle with 300 feet of radius, that means the radius of the pentagon is also 300 feet.

A pentagon can be divided in five equal isosceles triangle, where the vertex angle of each on is

[tex]\frac{360}{5}=72\°[/tex]

Now, each isosceles triangle can be divided in to equal right triangles with an angle equal to

[tex]\frac{72}{2}=36\°[/tex]

Additionally, the hypothenuse of each right triangle is the radius, so [tex]r=300ft[/tex].

We can find the leg that represent the height of the triangle by using trigonometric reasons

[tex]cos72\°=\frac{h}{300ft}\\ h=300cos72\°\\h\approx 93[/tex]

Where [tex]h[/tex] the height.

The base would be

[tex]sen72\°=\frac{b}{300ft}\\ b=300sen72\°\\b\approx 285[/tex]

Then, the are of one triangle would be

[tex]A=\frac{bh}{2}= \frac{(285)(93)}{2}=13252.5[/tex]

This means the area of one triangle is 13252.5 square feet.

However, a pentagon is formed by 5 triangles. So, the are would be

[tex]A_{pentagon}=5( 13252.5)=66262.5ft^{2}[/tex]

C

Explanation:

The order is this: Displacement --> Velocity --> Acceleration.  The velocity directly affects the displacement and the acceleration directly affects the velocity. (changing the acceleration changes the velocity which also changes the displacement).

To go forward in our order, find the slope of the curve/line.  To go backwards, find the area under the curve/line.  In this case, we are trying to find the displacement of the object, so we should find the area of a velocity-time graph.

e

Step-by-step explanation:

e

mathematically,

[tex]pressure = \frac{force}{area}[/tex]

but weight= Force.

given pressure

18N/cm^2

and Force = 9000N

making area the subject in the relation above.

[tex]Area = \frac{force}{pressure}[/tex]

substitute their values into the equation

[tex]Area = \frac{9000}{18}[/tex]

[tex]Area = 500 {cm}^{2}[/tex]

The interior of a pentagon can be modelled by 5 isosceles triangles.The interior angles are given by Î = 360 / 5 Î = 72° The sides of the triangles is equal to the radius, so x = 300 The other two angles are equal and are given by Φ = (180 - 72) / 2 Φ = 108 / 2 Φ = 54° The length of the outside leg is given by L = (x Sin Î) / Sin Φ L = (300 Sin 72) / Sin 54 L = 300(0.9511) / 0.809 L = 285.33 / 0.809 L = 352.7 The height is given by h² = x² - (1/2 L)² h² = 300² - [1/2 (352.7)]² h² = 90000 - (176.35)² h² = 90000 - 31099.3 h² = 58900.7 h = âš58900.7 h = 242.7 The area of one triangle is given by a = 1/2 (Lh) a = 1/2 [352.7(242.7)] a = 1/2 (85598.4) a = 42799.2 The area of the courtyard is 5 times that, so A = 5a A = 5(42799.2) A = 213996 Area of Courtyard = 213,996 sq. ft.

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