How to multiply matrices
Answers
3x3=6...3x3=6...6x6=36
neither
Step-by-step explanation:
Both statements are correct.
If matrix 1 has dimensions (r1, c1) and matrix 2 has dimensions (r2, c2), their product can be formed if c1 = r2. The resulting product matrix will have dimensions (r1, c2).
28,000
10,500
3,700
Step-by-step explanation:
Regular Premium
No.1 20 30
No.2 15 5
No.3 5 2
regular cost per gallon - 500
premium cost per gallon - 600
first, you multiply 20 & 500= 10,000 then, you multiply 30 & 600= 18,000.
next, you add them 10,000+18,000=28,000
and you repeat filling in the other numbers.
15*500 = 7,500 5*600 = 3,000 7,500 + 3,000 = 10,500
5*500 = 2,500 2*600 = 1,200 2,500 + 1,200 = 3,700
Given the matrix
[tex]\left[\begin{array}{cc}20&30\\15&5\\5&2\end{array}\right][/tex]
representing the number of thousands of gallons of regular and premium oil sold by the three stations of Tiger oil company and the matrix
[tex]\left[\begin{array}{c}500\\600\end{array}\right][/tex]
representing dolloars per thousands of gallons of regular and premium oil sold by Tiger oil company.
The matrix for total dollar volume of sales using matrix multiplication is given by:
[tex]\left[\begin{array}{cc}20&30\\15&5\\5&2\end{array}\right] \left[\begin{array}{c}500\\600\end{array}\right]= \left[\begin{array}{c}20(500)+30(600)\\15(500)+5(600)\\5(500)+2(600)\end{array}\right] \\ \\ = \left[\begin{array}{c}10000+18000\\7500+3000\\2500+1200\end{array}\right] =\left[\begin{array}{c}28000\\10500\\3700\end{array}\right][/tex]
Therefore, the total dolar volume of sales is per thousand of gallons of oil is given by:
[tex]\left[\begin{array}{c}28000\\10500\\3700\end{array}\right][/tex]
I just used my Ti 84
it is correct except for 3rd number
should be
-3
-6
-16
8
If asap i do 20 characters for spam filter and
yes it is
This is not fun
so
we mutiply the number of rows of the first matrix by the number of collumns of the second matrix
3*2 is the dimentions of the resulting matrix
you have
[tex] \left[\begin{array}{cccc}9&4&8&6\\2&0&3&1\\1&-2&5&0\end{array}\right] \left[\begin{array}{cc}12&2\\15&1\\3&9\\8&11\end{array}\right] =[/tex][tex]\left[\begin{array}{cc}9*12+4*15+8*3+6*8&9*2+4*1+8*9+6*11\\2*12+0*15+3*3+1*8&2*2+0*1+3*9+1*11\\1*12+-2*15+5*3+0*8&1*2+-2*1+5*9+0*11\end{array}\right][/tex]=[tex]\left[\begin{array}{cc}108+60+24+48&18+4+72+66\\24+0+9+8&4+0+27+11\\12+-30+15+0&2+-2+45+0\end{array}\right][/tex]=[tex]\left[\begin{array}{cc}240&160\\41&42\\-3&45\end{array}\right][/tex]
Yes, that is correct. I checked it on my calculator. Good job!
Yup, it looks good to me.