Help me please! Ratios and Rates! Worth 20 points help I need the answers in 45 minutes!Please get 3,4,5,6,7and 8 done I need help!! Thank you no links

11 answers
Question:

Help me please! Ratios and Rates! Worth 20 points help I need the answers in 45 minutes! Please get 3,4,5,6,7and 8 done I need help!! Thank you no links for websites are aloud thank you

[tex]Help me pleaseeeeeee! Ratios and Rates! Worth 20 points help I need the answers in 45 minutes! Pl[/tex]


Answers

3) 7:8  7 to 8   4) 40/100 = 2/5   5) 60 mph   6) 300 kph   7) Jane  8) Jon can go faster

Step-by-step explanation:

5) 120/2 =60

6) 900/3 =300

7) Tim =50/5= $10 an hour

Jane= 24/2 =$12 an hour

(1,8)

Step-by-step explanation:

5n6nj36ohino536nhon6hi35tgkn3;rktjnho3n5jmh3iorntphn35nyhi35nhin356ihn3io56nh356nh3i5nh6o3

Step-by-step explanation:

e. >

f. <

g. =

h. >

i. =

j. <

knapifnvqtv35yjnbi4nyb3n5 hi it is d

Step-by-step explanation:

Step-by-step explanation:

e. >

f. <

g. =

h. >

i. =

j. <

This is an advertisement to join a new animating/vocalist group called cartoonlens we specialize in animating, drawing, stroyboards, writing, song covers, vocalist, character voicings/character voice actors, etc.

Here is the l-ink for the form is anyone is interested in joining (its completely free and the only requirment is having a g-mail/e-mail that we can reach you at): https://docs.go-ogle.com/forms/d/e/1FAIpQLSc2mnQzMtqASFIq54b5H9qW4pbq47bo5WwVf_Ozf0DfTfXa5w/viewform

(remember to take that space bar out of go-ogle since i had to add that there since censors it)

Explanation:

You can download answer here

tinylnk.gq/5hoR

≈6.40312

Step-by-step explanation:

Aso sorry if i’m wrong

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.

[tex]Point z is equidistant from the sides of δrst. which must be true? ctzaszaszzsb[/tex]

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