HELP!! In AMNO, m M = (4x - 13), mZN = (2x – 13), andm20 = (5x + 19). Find mZN.

4 answers
Question:

HELP!!
In AMNO, m M = (4x - 13), mZN = (2x – 13), and
m20 = (5x + 19). Find mZN.

[tex]HELP!! In AMNO, m M = (4x - 13), mZN = (2x – 13), and m20 = (5x + 19). Find mZN.[/tex]


Answers

may i see the picture? it would a lot, xox

12cm

the answer is d

11 mintues is the naswer

x =-.20752

step-by-step explanation:

4^(x+2)=12

4^(x+2)=12

take the log base 4 on each side

log 4 (4^(x+2) = log 4(12)

we know log b(a^y) = y log b (a)

(x+2) log 4(4) = log 4 (12)

x+2 = log 4 (12)

we know   logb c = loga c/loga b

we want to convert to base 10   so a = 10

by default, we do not write the 10   c = 4   and b = 10

log4 10 = log 12/log 4

log4 10 = log 12/ log 4

x+2 = log 12/ log 4

subtract 2 from each side

x +2 -2 = log 12/ log 4 -2

x = 1.79248125 -2

x =-.20752

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