Five isomeric alkenes a-e each undergo catalytic hydrogenation to give 2-methylpentane. the ir spectra

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Question:

Five isomeric alkenes a-e each undergo catalytic hydrogenation to give 2-methylpentane. the ir spectra of these five alkenes have the following key absorptions (in cm-1): compound a: 912 (s), 994 (s), 1643 (s), 3077 (m) compound b: 833 (s), 1667 (w), 3050 (weak shoulder on c-h absorption) compound c: 714 (s), 1665 (w), 3010 (m) compound d: 885 (s), 1650 (m), 3086 (m) compound e: 967 (s), no absorption 1600-1700, 3040 (m) the alkene structures are given below. identify each compound.

Answers

Solution and Explanation:

Strong peak at 643cm−1 corresponds to alkene C=C stretching.

Medium peak at 3077cm−1 corresponds =C-H stretching.

Strong peaks at 912cm−1 and 994cm−1 corresponds to alkene =C-H bending. This tells the alkene is monosubstituted.

2. Weak peak at  3077cm−1 corresponds =C-H stretching.

The compound shows strong peak at 833cm−1 corresponds to alkene =C-H bending and weak peak at 1667cm−1 corresponds to alkene C=C stretching. This tells the alkene is trisubstituted.

3. Weak peak at 1665cm−1 corresponds to alkene C=C stretching.

Medium peak at 3086cm−1 corresponds =C-H stretching.

Strong peaks at 714cm−1 corresponds to alkene =C-H bending. This tells the alkene is cis-disubstituted.

4. Medium peak at 1643cm−1 corresponds to alkene C=C stretching.

Medium peak at 3010cm−1 corresponds =C-H stretching.

Strong peaks at 885cm−1 corresponds to alkene =C-H bending. This tells the alkene is gem-dialkylsubstituted.

5. Medium peak at 1650cm−1 corresponds to alkene C=C stretching.

Medium peak at 3040cm−1 corresponds =C-H stretching.

Strong peaks at 967cm−1 corresponds to alkene =C-H bending. This tells the alkene is trans-disubstituted.


[tex]Five isomeric alkenes A–E each undergo catalytic hydrogenation to give 2-methylpentane. The IR spect[/tex]

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