Find the value of y when x=3y=2x3y=0

54

Why? You need to put 3 in for x so you get
2(3)^3
3 to the third power is 3*3*3 which equals 27
2(27)
Now you must do 2 times 27 and you get 54

Hope this helps

1.a
2.c
3.b
4.784
5.part a: coefficient: 75     variable: d   constant: 25
part b: 75d+8w+25=
75*5+8*48+25=
375+384+25=
759+25=
784
part c: the constant would change, because there is no variable attached to the number.

2x^3 + 3y^2 − 17
Plug the value of the x and y
2(3)^3+3(4)^2-17
3^3=27
4^2=16
=2(27)+3(16)-17
=54+48-17
=102-17
=85

2x³ + 3y² - 17

Subtitute the values x = 3 and y = 4 to the expression:

2 · 3³ + 3 · 4² - 17 = 2 · 27 + 3 · 16 - 17 = 54 + 48 - 17 = 102 - 17 = 85

2x³ + 3y² - 17 =
2*(3)³ + 3*(4)² - 17 =
2*27 + 3*16 - 17 = 
54 + 48 - 17 =
85 ← Answer

2x³ + 3y² − 17 = 2*(3)³ + 3*(4)² - 17 = 2*27 + 3*16 - 17 = 54 + 48 - 17 = 85.

85

Step-by-step explanation:

2x^3 + 3y^2 − 17

2(3)^3 + 3(4)^2 − 17

2*27 + 3*16 -17

54  + 48 -17 = 85

85

Step-by-step explanation:

I assume by 2x3 you mean 2x^3 and 3y2 means 3y^2. If so then just plug in the values:

2x^3 + 3y^2 - 17 = ?

2(3)^3 + 3(4)^2 - 17 = ?

2(27) + 3(16) - 7 = ?

54 + 48 - 17

102 - 17 = ?

85 = ?

85

Step-by-step explanation:

Substitute x = 3 and y = 4 into the expression and evaluate, that is

2(3)³ + 3(4)² - 17

= 2(27) + 3(16) - 17

= 54 + 48 - 17

= 102 - 17

= 85

B. 85

Step-by-step explanation:

We have been given an expression [tex]2x^3+3y^2-17[/tex]. We are asked to find the value of expression, when [tex]x=3[/tex] and [tex]y=4[/tex].

To find the value of our given expression, we will substitute [tex]x=3[/tex] and [tex]y=4[/tex] in our expression as:

[tex]2(3)^3+3(4)^2-17[/tex]

[tex]2*27+3*16-17[/tex]

[tex]54+48-17[/tex]

[tex]102-17[/tex]

[tex]85[/tex]

Therefore, the value of expression at the given values would be 85.

What are the choices

no

step-by-step explanation: