Find the area of the figure15 cm21 cm20 cm

12 answers
Question:

Find the area of the figure
15 cm
21 cm
20 cm

[tex]Find the area of the figure 15 cm 21 cm 20 cm[/tex]


Answers

The correct option is third. The area of the figure is 25 cm square.

Explanation:

It is given that Each small square on the grid is 1 cm².

In the given figure there are 2 congruent parallelograms and 4 congruent triangles. As shown in figure below.

From the figure it is noticed that the length and breadth of the parallelogram is 4 and 3 respectively.

Area of the parallelogram,

[tex]A=length\times breadth[/tex]

[tex]A=4\times 3=12[/tex]

Area of a parallelogram is 12 cm². So, the area of 2 parallelogram is

[tex]12\times 2=24[/tex]

The height of the triangle is 0.25 and the base of the each triangle is 2.

Area of a triangle is,

[tex]A=\frac{1}{2} \times base \times height[/tex]

[tex]A=\frac{1}{2} \times 2 \times 0.25=0.25[/tex]

Area of one triangle is 0.25 cm², so the area of 4 triangles are 1 cm².

Total Area of the figure is,

[tex]Area=24+1=25[/tex]

Therefore, the total area is 25 cm².

125

Step-by-step explanation:

divide the Figure into 3 parts

1 st = 5 X 10 =50

2nd = 5×10 =50

3rd = 5×5 = 25

total = 50+50 + 25 = 125

19,440 Square Yards

Explanation:

15 times 4 is 60, 6 times 6 is 36, 36 times 60 is 2,160, and 2,160 times 9 is 19,440.

25 units²

Step-by-step explanation:

Count each whole box as one cm and count the ones that aren't whole as half a cm and you get 25 units²

45

Step-by-step explanation:

I believe it is 100 ft

Step-by-step explanation:

idk

Step-by-step explanation:

Do you have a pic you can post of the figure?

I think the answer is c I’m not 100% sure

It is 800 because you multiply each one by 2

answer: a and c are correct

step-by-step explanation:

the +5 is the vertical translation

the added negative symbol in front is the reflection over the y-axis

[tex]Which statements describe one of the transformations performed on f(x) = x^2 to create g(x) = -(x -[/tex]

The answer is 76° i believe

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