Find the Area of the figure below, composed of a rectangle and one semicircle, with another semicircle removed. Round to the nearest tenths

4 answers
Question:

Find the Area of the figure below, composed of a rectangle and one semicircle, with another semicircle removed. Round to the nearest tenths place. ​

[tex]Find the Area of the figure below, composed of a rectangle and one semicircle, with another semicir[/tex]


Answers

The area is 140 units.
The semicircle on the right side can be moved to fill in the missing semicircle to make it a regular rectangle.
Meaning 14 (10) would give the correct answer.

Given:

The given figure consists of a rectangle, a semicircle and another semicircle removed from it.

The length of the rectangle = 15 unit

The width of the rectangle = 10 unit

The diameter of the semicircle = 10 unit

So, the radius of the semicircle = 5 unit

To find the formula of given fig.

Formula:

The area of the given fig is

[tex]A = A_{1} +A_{2}-A_{3}[/tex]

where,

[tex]A_{1}[/tex] be the area of the rectangle

[tex]A_{2}[/tex] be the area of the semicircle

[tex]A_{3}[/tex] be the area of the semi circle that needs to remove

Area of the rectangle [tex]A_{1} = lb[/tex], where, l be the length and b be the width

The area of the semicircle [tex]A_{2}[/tex] = [tex]\frac{1}{2}\pi r^{2}[/tex]

The area of the semicircle [tex]A_{3}[/tex] = [tex]\frac{1}{2}\pi r^{2}[/tex]

where, r be the radius.

Now,

Putting, l=15 and b = 10 we get,

[tex]A_{1} = (15)(10)[/tex] sq unit

[tex]A_{1} = 150[/tex] sq unit

Putting, r = 5 and π = 3.14 we get,

[tex]A_{2} = \frac{1}{2} (3.14)(5^{2} )[/tex] sq unit

[tex]A_{2} = 39.25[/tex] sq unit

Similarly, [tex]A_{3} = 39.25[/tex] sq unit

Therefore,

The area of the given figure = (150+39.25-39.25) sq unit

= 150 sq unit

Hence,

The area of the given figure is 150 sq unit.

step-by-step explanation:

what are the statements? and what do you mean by "216 2 1 6"?

answer: do we write it

step-by-step explanation:

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