Fast what is the difference in the areas of a circle with diameter 4 m and a circle with diameter 6

16m2. hope this helps. you have the formula A=pi r^2. plug in the numbers then subtract.

Option b is correct

16 [tex]m^2[/tex]

Step-by-step explanation:

Area of circle (A) is given by:

[tex]A = \pi r^2[/tex]

where, r is the radius of the circle.

As per the statement:

the areas of a circle with diameter 4 m

Formula for Diameter(d) is:

[tex]d = 2r[/tex]

⇒[tex]4 =2r[/tex]

Divide both sides by 2 we get;

r = 2 m

then;

[tex]A= \pi \cdot (2)^2 = 4 \pi[/tex]

It is also given: a circle with diameter 6 m

Similarly;

[tex]6 = 2r'[/tex]

⇒[tex]r' = 3 m[/tex]

then;

[tex]A' = \pi \cdot 3^2 = 9 \pi[/tex]

We have to find the difference in these areas:

[tex]A'-A = 9 \pi -4 \pi = 5 \pi[/tex]

Use [tex]\pi = 3.14[/tex]

then;

[tex]A'-A = 5 \cdot 3.14 = 15.7 m^2 \approx 16 m^2[/tex]

Therefore, the difference in the areas of a circle with diameter 4 m and a circle with diameter 6 m is, [tex]16 m^2[/tex]

The 4 m diameter circle's area is 12.56 and the 6 m one is 28.26, so um,  15.7 is the difference, hope it helps!

B - 16 m2

solve:
(pi)x2^2=12.6

(pi)x3^2=28.3

28.3-12.6=15.7

round to 16

Hello!

To solve this you need to use the equation to find the area of a circle which is

[tex]A = \pi r^{2}[/tex]

A is area
r is radius

Solve both circles
------------------------------------------------------------------------------------------------------
Circle 1
[tex]A = \pi 4^{2}[/tex]

Square the number

[tex]A = 16 \pi[/tex]
------------------------------------------------------------------------------------------------------
Circle 2

A = [tex]\pi 6^{2}[/tex]

Square the number

[tex]A = 36 \pi[/tex]
------------------------------------------------------------------------------------------------------
Finding the answer

To get the answer you subtract the numbers

[tex]36 \pi - 16 \pi = 20 \pi[/tex]

The difference is [tex]20 \pi[/tex] which is about 62.83 units

Hope this helps!

Hi there,

Area of a circle with 4m = π(2)² = 4π m²
 
Area of a circle with 6m = π(3)² = 9π m²

Difference = 9π - 9π = 5π = 16 m² (nearest m²)

16 m² (Answer B)

Hope it helps,
TF

So the formula for the area of the circle is [tex]A=\pi r^2[/tex] . To find the radius is divide the diameters by 2, which in this case its 2 and 3. Now we can find the areas.

[tex]A= \pi 2^2 \\ A=4 \pi[/tex]

[tex]A= \pi3^2 \\ A=9 \pi[/tex]

Now just subtract the areas: [tex]9 \pi -4 \pi =5 \pi[/tex]

The difference in areas is 5 pi, or 15.71.