Factories often add filler when making meatballs sold by the bag. One factory obtained 90 kg of beef from overseas. They

6 answers
Question:

Factories often add filler when making meatballs sold by the bag. One factory obtained 90 kg of beef from overseas. They want to add 1.4 oz of filler for each pound of beef. How many ounces of filler will the factory need in order to make meatballs out of this shipment of beef? Use 1 lb=0.45 kg and do not round any computations.

Answers

 The correct option is (C) 28.2 oz.

Step-by-step explanation:  Given that a recipe calls for 0.800 kg of flour.

We are to find the number of ounces of flour that the recipe needs.

Given that

1 lb=16 oz  and  1 lb = 0.454 kg

We will be using the UNITARY method for solving the given problem.

We have

0.454 kg = 1 lb

So, 1 kg will be equal to [tex]\dfrac{1}{0.454}~\textup{lb}.[/tex]

Therefore, 0.8000 kg is equal to

[tex]\dfrac{1}{0.454}\times 0.800=1.762~\textup{lb}.[/tex]

Now, 1 lb = 16 oz.

So, 1.762 lb = 16 × 1.762 = 28.19 = 28.2 oz.

Thus, the recipe needs 28.2 oz of flour.

Option (C) is CORRECT.

[tex]\frac{25,000 oz}{1} * \frac{1LB}{16oz} * \frac{0.454 KG}{1 LB}[/tex] = 723.5625 kg

B

dont mind me just tryna figure this out ignore till i figure it

Step-by-step explanation:

First, you divide the given measurement by 16 to find how many pounds you have:

[tex]\frac{25500}{16} = 1593.75[/tex]

Now, multiply that by 0.454 to get how many kilograms you have:

[tex]1593.75*0.454=723.56[/tex]

Approximately, 724 kg, or choice B.

For this case we must take into account the following conversions of units:
 1lb = 16 oz
 1 lb = 0.454 kg
 Applying the conversion of units we have:
 (0.800) * (1 / 0.454) * (16/1) = 28.1938326
 Rounding off we have:
 28.2 oz
 
 it needs 28.2 oz of flour

It is 100 Bc I know math

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