# F (x) = StartRoot 5 x minus 5 EndRoot + 1

## Answers

1. 5x-5 greater than or equal to 0 , 2. greater than or equal to , 1

Step-by-step explanation:

just did it on edg

[tex]5x-5 \ge 0[/tex]

This is the same as [tex]x-1 \ge 0[/tex]

========================================================

Explanation:

We have [tex]f(x) = \sqrt{5x-5}+1[/tex]

The stuff under the square root (this stuff is called the radicand) is what we'll focus on (the +1 at the end does not affect the domain at all). We want this to be 0 or larger. This is to avoid applying the square root to negative values, which leads to complications.

So 5x-5 must be 0 or larger meaning we write [tex]5x-5 \ge 0[/tex]

Optionally we can divide all three terms (5x, -5 and 0) by 5 to go from [tex]5x-5 \ge 0[/tex] to [tex]x-1 \ge 0[/tex]

If you wanted to solve for x, you would get [tex]x \ge 1[/tex] to set up the domain. Meaning that x = 1 is the smallest x value you can plug into the function. The x value can be anything larger than 1 as well.