Express 56 as the product of its prime factors.

2,2,2,7.............or
[tex]{2}^{3} \times 7[/tex]

2,3,5,7, 11 ,13,17, 19

56  =   2 x 2 x 2 x 2 x 7

7 x 2 x 2 x 2

Step-by-step explanation:

So 7x8 = 56; 7 is prime, but 8 can be factored further; 8 = 4x2, but the 4 can be factored; 2x2

So now you have the prime factorization of 56= 7 x 2 x 2 x 2

The factors of 56 are 7 and 8
7 is a prime number 
8 can be factored in 2*2*2
56 as a product of its prime numbers: 7*2*2*2

 [tex]756 = 2 ^{2} *3^3*7[/tex]

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➷ 56/2 = 28

28/2 = 14

14/2 = 7

Therefore 2 x 2 x 2 x 7 = 56

Your answer is [tex]2^{3} * 7[/tex]

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[tex]2^{3} *7[/tex]

Step-by-step explanation:

[tex]56=2*28[/tex]

[tex]56=2*2*14[/tex]

[tex]56=2*2*2*7[/tex]

Thus, [tex]56=2^{3}*7[/tex]