# Determine the molar mass of barium sulfide, bas

## Answers

169.39 g/mol

Explanation:

5.30x10^22 x 261.35g/6.02x10^23 = 23.01 g Ba(NO3)2

6×10^23 molcules implies 261.35 gm

5.3×10^22 molcules implies 5.3×10^22×261.35/6×10^23

=

23.1 gm

23.0 is the answer

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23.0 is the answer

answer: the mass of given formula unit of barium nitrate is 23.001 grams

explanation:

according to mole concept:

1 mole of a compound consists of formula units.

and mass of 1 mole of barium nitrate is 261.35 grams.

therefore, mass of formula units is 261.35 grams.

so, formula units will consist of

hence, the mass of given formula unit of barium nitrate is 23.001 grams.

The Avogadro's number is [tex]N_A = 6.02289 *10^{23}[/tex]

Explanation:

From the question we are told that

The edge length is [tex]L = 5.02 * 10^{-8} \ cm= \frac{5.02 * 10^{-8} }{100} = 5.02 * 10^{-10}[/tex]

The density of the metal is [tex]\rho = 5.30\ g/cm^3 = 5.30 * \frac{g}{cm^3} * \frac{1*10^6}{1*10^3} = 5.30 *10^3kg/m^3[/tex]

The molar mass of Ba is [tex]Z = 137.3 \ g/mol = \frac{137.3}{1000} = 0.1373 \ kg / mol[/tex]

Generally the volume of a unit cell is

[tex]V = L^3[/tex]

substituting value

[tex]V = [5.02 *10^{-10}]^3[/tex]

[tex]V = 1.265*10^{-28}\ m^3[/tex]

From the question we are told that 68% of the unit cell is occupied by Ba atoms and that the structure is a metal which implies that the crystalline structure will be (BCC),

The volume of barium atom is

[tex]V_a = \frac{V}{2} * 0.68[/tex]

substituting value

[tex]V_a = \frac{ 1.265*10^{-28}}{2} * 0.68[/tex]

[tex]V_a = 4.301 *10^{-29} \ m^3[/tex]

The Molar mass of barium is mathematically represented as

[tex]Z = N_A V_a * \rho[/tex]

Where [tex]N_A[/tex] is the Avogadro's number

So

[tex]N_A = \frac{ Z}{ V_a * \rho}[/tex]

substituting value

[tex]N_A = \frac{ 0.1373}{ 4.301*10^{-29} * 5.3*10^{3}}[/tex]

[tex]N_A = 6.02289 *10^{23}[/tex]

Hello!

261.35 g 6.02x10²³ formula units

? g 5.30 x10²² formula units

( 5.30x10²² ) x 261.35 / 6.02x10²³

= 1.385x10²⁵ / 6.02x10²³

= 23.0 g

I hope this helps! Have a bless day!

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