Determine the center and radius of the circle described by the equation.(x+2)2+(y−5)2=9center= (do not put a link please they don't work)

12 answers
Question:

Determine the center and radius of the circle described by the equation. (x+2)2+(y−5)2=9
center= (do not put a link please they don't work)

Answers

H⁣⁣⁣⁣ere's l⁣⁣⁣ink t⁣⁣⁣o t⁣⁣⁣he a⁣⁣⁣nswer:

bit.[tex]^{}[/tex]ly/3a8Nt8n

[tex](x-h)^2+(y-k)^2=r^2\\
(h,k) - \text{center}\\\\
(x+9)^2+(y+4)^2=36\\
\text{center}=(-9,-4)\\
r=\sqrt{36}=6[/tex]

2 (x + y) = 29

2 (x + y - 2) = 25

y = 29/2 - x

Expanded forms:

2 x + 2 y - 4 = 25

2 x + 2 y - 29 = 0

Real solution:

y = 29/2 - x

Solution:

y = 29/2 - x

Solution for the variable y:

y = 1/2 (29 - 2 x)

Step-by-step explanation:

hope its helpss

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bit.[tex]^{}[/tex]ly/3a8Nt8n

center: (-1,5)

radius: 6

Step-by-step explanation:

Explanation is in the file

cutt.ly/zxt1ipy

H⁣⁣⁣⁣ere's l⁣⁣⁣ink t⁣⁣⁣o t⁣⁣⁣he a⁣⁣⁣nswer:

bit.[tex]^{}[/tex]ly/3a8Nt8n

I uploaded the answer to a file hosting. Here's link:

cutlnk.ml/0tj3C

Step-by-step explanation:

radius = √75 = 5√3 ≅ 8.66 units

Step-by-step explanation:

What are the center and radius of the circle described by the equation x2 + y2 + 6x + 10y + 18 = 0?

Center (3.5); Radius 4

Center (-3,-5); Radius 4

O Center (3,5); Radius 16

O Center (3.5); Radius 10

x² + y²+ 6x + 10y + 18 = 0

x² + 6x + y² + 10y = -18

x² + 6x + 9 + y² + 10y + 25 = -18 + 6 + 9

x² + 3x + 3x + 9 + y² + 5y + 5y + 25 = -3

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[tex]Write the order pair that represents yz. then find the magnitude of yz. y(-2,5), (1,3)[/tex]

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