# Darius takes his family on an afternoon boat ride.Going through York Canal, he drives 5 miles in 15 minutes.Later on as he crosses Stover Lake, he

###### Question:

Later on as he crosses Stover Lake, he drives 30 minutes at the same average speed.

Which statement about the distances is true?

## Answers

C- the distance traveled in York canal is one half the distance traveled on strover lake

-HOPE IT HELPS

Step-by-step explanation:

Given that Darius takes his family on an afternoon boat ride.

First he drives 5 miles in 15 minutes.

Next he drives 30 minutes at the same rate i.e. 5 m/15 min or 20 miles/hour

Since speed is 20 miles/hour, it follows that he travels 10 miles in 30 minutes.

So the true statement is

he travels 10 miles in 30 minutes

Concept used:

Distance travelled = speed x time

Speed =average speed normally denoted by miles per bour

The distance traveled in York Canal is one half the distance traveled on Stover Lake.

Btw, I guessed it and it said it was correct so yeah... (imagine math)

There are no answer choices but if he drove 5 miles in 15 minutes and then traveled about at the same speed in 30 minutes which means he drove 5 more miles which makes it 10 so he is driving at 20mph

-hope it helps

I see what you mean, there are no statements, could this be a misprint? Yes you're right he would go 10 miles in 30 minutes.

In first case, the average speed is (5/15) miles per minutes = (1 /3 ) miles per minutes;

In second case, the distance traveled in York Canal is 30 x ( 1 / 3) = 10 miles;

But, 10 + ( 10 ÷ 2 ) = 10 + 5 = 15 miles;

The correct answer is C)!

The statement that is true would be later on as he crosses Stover Lake, he drives 30 minutes at the same average speed. Hope this helps