Convert 338 L at 63.0 atm to its new volume at standard pressure.

The new volume at standard pressure of 1 atm is 21294 liters.

Explanation:

Data given:

Initial volume of the gas V1 = 338 liters

initial pressure on the gas P1 = 63 atm

standard pressure as P2 = 1 atm

Final volume at standard pressure V2 =?

The data given shows that Boyle's law equation is to used:

P1V1 = P2V2

rearranging the equation to calculate V2,

V2 = [tex]\frac{P1V1}{P2}[/tex]

Putting the values in the equation:

V2 = [tex]\frac{338X63}{1}[/tex]

     = 21294 L

as the pressure on the gas is reduced to 1 atm the volume of the gas increased incredibly to 21294 litres.

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