Can someone me with numbers 10,11,12 plzzz show work i need pl

10 answers
Question:

Can someone me with numbers 10,11,12 plzzz show work i need pl

[tex]Can someone me with numbers 10,11,12 plzzz show work i need pl[/tex]


Answers

  10. JL = 4

  11. m∠KML = 45°

  12. see below for a full list of angle measures; x = 30

Step-by-step explanation:

10. In the square, the diagonals are both the same length, and point N is their midpoint. That means ...

  KM = 2·JN

  4z -8 = 2(4z -10) . . . . substitute the given expressions

  4z -8 = 8z -20 . . . . . .eliminate parentheses

  12 = 4z . . . . . . . . . . . .add 20-4z to both sides

  KM = 12 -8 = 4 . . . . . substitute for 4z in the expression for KM

  JL = KM = 4

__

11. All the sides and angles that look like they're the same measure are the same measure. Any angle not 90° is 45°. m∠KML = 45°

__

12. For this, you make use of the properties of a rhombus. The diagonals of a rhombus are perpendicular bisectors of each other, so all of the angles where the diagonals meet are 90°.

Then within each triangle, the angles not 50° are their complement, 40°.

Angles in opposite corners are congruent to each other, and each diagonal bisects the corner angle. So ...

  ∠GHJ = ∠GKJ = 100°

  ∠GHK = ∠JHK = ∠GKH = ∠JKH = 50°

  ∠HGK = ∠HJK = 80°

  ∠HJG = ∠KJG = ∠KGJ = ∠KJG = 40°

We have already said the central angle is 90°, so ...

  (5x -60)° = 90°

  x -12 = 18 . . . . . . divide by 5°

  x = 30 . . . . . . . . add 12


[tex]Can someone me with numbers 10,11,12 plzzz show work i need pl[/tex]

10 would be real and a rational number and 11 would be real and a integer

10. 2k+3
12. p-6
15. 5 divided by n

106.09x^2 I think this is the answer but just in case do 106.09x106.09 then add the x

15.64800 , the answer would be 15.64800
I hope this helped, love!!

-10-15= -25

-3+(-5) - positive sign and negative sign = negative sign

-3-5= -8

-5x - 2y² + 1

Use the substitution method

-5(4)-2(-2)^2+1

(-2)(-2)= 4

-20-8+1= -28+1

= -27

Answers :

-10-15= -25

-3+(-5)=-8

-5x - 2y² + 1= -27

1) For, m =  3/4 ,  (0,4)  , 4y - 16 - 3x = 0  is the equation of line.

2) For, m =  4 ,  (-2,-5)  , y -  4x - 4  = 0  is the equation of line.

3) For, m =  -1/3 ,  (4,-1)  , x + 3y -1  = 0  is the equation of line.

Step-by-step explanation:

If m is the slope and (x0,y0) is the point on any given equation, then

by POINT SLOPE FORMULA:

The line equation is given as (y - y0) = m (x -x0)

Now , here:

1) m =  3/4 , (x0, y0) = (0.4)

So,, the equation of line is [tex](y-4) = \frac{3}{4} (x-0)\\or, 4(y-4) = 3x[/tex]

on simplification,  4y - 16 - 3x = 0  is the equation of line.

2) m =  4 , (x0, y0) = (-2.-5)

So,, the equation of line is [tex](y-(-5)) = 4 \times (x-(-2))\\or, (y+4) = 4(x+2)[/tex]

on simplification, y -  4x - 4  = 0  is the equation of line.

3) m =  -1/3 , (x0, y0) = (4, -1)

So,, the equation of line is [tex](y-(-1)) = \frac{-1}{3} (x-4)\\or, 3(y+1) = -(x-4)[/tex]

on simplification,   x + 3y -1  = 0  is the equation of line.

Idk if your teacher will mind if the y-axis and the x-axis were different (x goes by 1's, y goes by 45) I also forgot to put a line....


To find the slope, use the slope formula and plug in 2 points. I will use (3, 135) and (5,225):

[tex]m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}[/tex]

[tex]m=\frac{225-135}{5-3}[/tex]

[tex]m=\frac{90}{2}[/tex]

m = 45


The slope is 45. This means that every minute, 45 words are something(typed/written/read - idk)


[tex]Can someone me with number 10 : ([/tex]

m(PRS) = 98°

m(PRQ) = 3x-8°

m(QRS) = 2x+6°

Also,

m(PRS) = m(PRQ)+m(QRS)

98 = 3x-8 + 2x+6

98 = 5x-2

98+2 = 5x

5x = 100

x = 20°

So, now we put x = 20° in m(QRS) given

m(QRS) = 2x-6 = 2(20)-6 = 40-6 = 32°

Therefore, m(QRS) = 32°

Please mark Brainliest if this helps!

Step-by-step explanation:

The expressions for the above questions are given below:

[tex]10) \: \: 2k + 3 \\ \\ 12) \: \: p - 6 \\ \\14) \: \: 5 \div n[/tex]

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