Can a quadratic function in stadard form, with a=1,bewritten in vertex form?​

Where’s the

step-by-step explanation:

given that there are two triangles j'k'l' and jkl>

the former is got by dilating the second one.

when drawn on a grid, (graph paper) coordinates of vertices of first triangle is

(6,12)j, (9,6)k and (12,9)l

side jk has length = distance between j and k

=[tex]\sqrt{(9-6)^{2} +(12-6)^{2} } \\=\sqrt(45)=3\sqrt(5)[/tex]

side j'k'=distance between j' and k'

=[tex]\sqrt{(3-2)^{2} +(2-4)^{2} } \\=sqrt(5)[/tex]

ie j'k'l' has sides 1/3 of that of corresponding sides of jkl.

hence scale factor of 1/3 is used to get j'k'l'from jkl

answer: can you give the

step-by-step explanation:

the answer is 5/14.

hope this .