Asap 40 pts + brainliest to right/best answer
Question:
[tex]Asap 40 pts + brainliest to right/best answer[/tex]
Answers
-5
Step-by-step explanation:
∛-25 × ∛5
= ∛-75
= ∛(-5)^3
= - 5
a
Step-by-step explanation:
(-25)^⅓ × 5^⅓
(-25 × 5)^⅓
(-125)^⅓
(-5)³^⅓
-5
The answer is D
Step-by-step explanation:
Factor and set each set equal to zero to get x=0,2,-1,1
A) 3log(x)+2log(y)-4log(z)
You should get the app Socratic it will help you a lot.
B
Step-by-step explanation:
(-2x³ - 4x²+ 9x² + 18x - 19x - 38 + 40)
÷ (x + 2)
[-2x²(x+2) + 9x(x+2) - 19(x+2) + 40]
÷ (x+2)
-2x² + 9x - 19 + 40/(x+2)
b
Step-by-step explanation:
(-2x³ - 4x²+ 9x² + 18x - 19x - 38 + 40)
÷ (x + 2)
[-2x²(x+2) + 9x(x+2) - 19(x+2) + 40]
÷ (x+2)
-2x² + 9x - 19 + 40/(x+2)
B
Step-by-step explanation:
2 || 1 - 4 6 - 4
2 -4 4
1 -2 2
x^2 - 2x + 2 with no remainder.
Looks like the answer is B
Note: Note that the two in x - 2 changes sign. That always happens when using synthetic division as long the number in front of the x is positive.
Because it is a fraction ( division) rewrite as:
log (5x) - log (4y)
Rewrite log 5x as log 5 + log x
Rewrite log 4y as log 4 + log y
Now you have log 5 + log x - log 4 + log y
Apply distributive property:
log 5 + log x - log 4 - log y
The answer is B.
D
Step-by-step explanation:
x¹³ - 2x¹² - x¹¹ + 2x¹⁰ = 0
x¹⁰(x³ - 2x² - x + 2) = 0
x¹⁰ [x²(x - 2) - (x - 2)] = 0
x¹⁰(x² - 1)(x - 2) = 0
x = 0 (multiplicity 10)
x = 1
x = -1
x = 2
see explanation
Step-by-step explanation:
Using the coefficients of the polynomial and evaluating for h = - 3
- 3 | 1 - 4 - 9 36
↓ - 3 21 - 36
1 - 7 12 0 ← remainder
Since remainder is 0 then (x + 3) is a factor, so
y = (x + 3)(x² - 7x + 12)
To factor the quadratic
Consider the factors of the constant term (+ 12) which sum to give the coefficient of the x- term (- 7)
The factors are - 4 and - 3, since
- 4 × - 3 = + 12 and - 4 - 3 = - 7, then
x² - 7x + 12 = (x - 4)(x - 3), and
y = (x + 3)(x - 4)(x - 3)
understand that i don't know the answers
will someone answer his question
[tex]Been stuck on this one way to long need[/tex]75
step-by-step explanation: