An employee of a company gets a three-digit lock code to enter the building the digits could be 1, 5, or 7 identify the lock

10 answers
Question:

An employee of a company gets a three-digit lock code to enter the building the digits could be 1, 5, or 7 identify the lock codes in the sample space that have at least two fives
a.) 155, 551, 555, 557, 755
b.) 155, 515, 551, 557, 575, 755
c.) 155, 515, 551, 557, 575, 755
d.) 115, 151, 155, 157, 175, 511, 515, 517, 551, 555, 557, 571, 575, 577, 715, 751, 755, 757, 775

Answers

a, b, c

Step-by-step explanation:

Decreasing Function

Explanation:

I'm confused, but I'm still gonna try and answer

40

Step-by-step explanation:

56

Step-by-step explanation:

Parenthesis (there is no parenthesis) Exponent (there are no exponents) Multiplication (there is no multiplication. Division (there is division [55÷55]{so we do that 1st}) Add (we have adding) Subtract (no subtraction) Divide first 55 + 55 ÷ 55​ => 55÷55+55 55÷55=1 add1+55 =56 I hope that makes sense

5×11=55

Step-by-step explanation:

if 55= 5× as many as 11

55=5×11

ik it doesn't make sense:(

f=55=466

f+55-55=466-55

Retail Price = $155

Step-by-step explanation:

The retail price is 55% MORE than the manufacturer buying price.

The manufacturer buying price is $100. So the retail price would be 55% MORE.

Firstly,

55% in decimal is:

55/100 = 0.55

Now 55% of 100 is:

0.55 * 100 = $55

So, the retail price is $55 MORE, so the retail price is:

100 + 55 = $155

Retail Price = $155

Step-by-step e Then ... In other words, whole numbers are the counting numbers and zero. ... How are the types of number related? ... The natural numbers are all whole numbers, excepting 0. 0 is a ... A percent that is equal to .0033 as a decimal and 33/10000 as a fraction.

xplanation:

Step-by-step explanation:

55 + 55 ÷ 55

= 55 + 1

= 56

Hope it will help :)

The correct answer would be B-80/200.

Allele frequency is defined as relative occurrence of the allele at a particular locus in a given population.

We have a sample population of 100 chickens where

Frequency of homozygous dominant trait (CC) =  45

Frequency of homozygous recessive trait (cc) = 25

Frequency of heterozygous dominant trait (Cc) = 30

Total alleles would be = 100 x 2 = 200

Total number of observed copies of C (dominant allele) = (45 x 2) + 30 = 120

Similarly, number of observed copies of c (recessive allele) = (25 x 2) + 30 = 80.

Hence, the frequency of allele C = 120/200 = 0.6

Frequency of allele c = 80/200 = 0.4

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