Alison has $1.60 worth of nickels and dimes in her coin purse. she has 11 more nickels

8 answers
Question:

Alison has $1.60 worth of nickels and dimes in her coin purse. she has 11 more nickels than dimes. how many of each coin does she have? nickles and dimes

Answers

32 nickles and 42 dimes

I just took the test and nickles were 18, dimes were 7.

Let the number of nickles be x and the number of dimes be y, so that means

0.05x + 0.1y=1.6

5x+10y=160...1

x=y+11...2


Put 2 into 1 that would give you

5(y+11)+10y=160

5y+55+10y=160

15y=160-55=105

y=105/15=7

x=7+11=18

So she has 18 nickels and 7 dimes

n=11+d

0.05n +0.10d = 1.60

0.05(11+d) + 0.10d = 1.60

0.55 + 0.05d + 0.10d = 1.60

0.55 +0.15d =1.60

0.15d = 1.05

d = 1.05/0.15 = 7 dimes

7 +11 = 18 nickels

7 dimes = 7 *0.10 = 0.70

18 nickels = 0.05*18 = 0.90

0.90 +0.70 = 1.60


A nickel = 5 cents = $0.05
A dime = 10 cents = $0.10

Let the number of nickels be x and the number of dimes be y, then
0.05x + 0.1y = 1.6
5x + 10y = 160 . . . (1)
x = y + 11 . . . (2)

Putting (2) into (1) gives\
5(y + 11) + 10y = 160
5y + 55 + 10y = 160
15y = 160 - 55 = 105
y = 105/15 = 7
x = 7 + 11 = 18

Therefore, He has 18 nickels and 7 dimes.

Alison has 18 dimes and 7 nickels

the square root of what number? if you add that, then someone will probably answer the question.

answer: i wpould go with c

step-by-step explanation:

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