Aline is perpendicular to another line m2= (-1/m1), where m1 is the slope of the original

12 answers
Question:

Aline is perpendicular to another line m2= (-1/m1), where m1 is the slope of the original line and m2 is the slope of the perpendicular line. which of the following equations represents the line that passes through the point (-2,1) and is perpendicular to the line below?

Answers

-3a+b=-3 => a=b+1 => 
12a+b=2 => 12(b+1)+b=2 => b = -10/13 => a=3/13

y=3/13x-10/13  - does not exist!

2 ONLY

Step-by-step explanation:

O

both are right

Step-by-step explanation:

okay so you already know that the y-intercept is 4 since a point is (0, 4)

but not to find the slope you can use the y2-y1/x2-x1

16 - 4/ -8 - 0 = 12/-8 = 3/-2

or

4 - 16/ 0 - (-8) = -12/8 = -3/2

it doesnt matter which you plug in first

so we know the slope (m) is -3/2 and the y-intercept (b) is 4, now to put it into an equation:

y = mx + b

y = -3/2x + 4

also im going to put this in slope-intercept form

3x + 2y = 8

-3x           -3x

2y = -3x + 8

/2         /2

y = -3/2x + 4

y = -3/2x + 4 = y = -3/2x + 4

so both answers equal each other, meaning they both are right

First, find the slope of the line that goes through the 2 given points, which you should know how to do.  Call it m.  Then a perpendicular line must have a slope of -1/m.  The slope-intercept form of the equation you seek is

y = (-1/m)x + b,

where b is any real number.  Examine the list of choices, and pick any that have a slope of -1/m.

Hey there again!

First, let's find the slope of this line. We will divide the difference in the y's by the difference in the x's.

[tex]\frac{y}{x} =\frac{2+8}{0+2} =\frac{10}{2} = 5[/tex]

Our slope is 5, so our equation should look like this so far.

y=5x+b

But, the only answer that matches having a slope of 5 is B, so we don't even need to finish!

Therefore, our answer is B: y=5x+5

I hope this helps! Have a great day!

Option A is correct

A. Neither

Step-by-step explanation:

Given:

Two points are given (2, 15) and (0, 5)

Let [tex](x_{1}, y_{1})=(2,15)[/tex] and [tex](x_{2}, y_{2})=(0,5)[/tex]

The slope of the line [tex]m=\frac{y_{2}- y_{1}}{x_{2}- x_{1}}[/tex]

Put all known value in above equation.

[tex]m=\frac{5- 15}{0- 2}[/tex]

[tex]m=\frac{-10}{-2}[/tex]

[tex]m=5[/tex]

So the slope of the line [tex]m=5[/tex].

The equation of the is

[tex]y=mx+b[/tex] -------------------(1)

Where m is the slope of the line and b is y-intercept of the line.

Take point (0, 5) to compute the value of b.

Put [tex]x=0,y=5\ and\ m=5[/tex] in equation 1.

[tex]y=mx+b[/tex]

[tex]5=5(0)+b[/tex]

[tex]5=0+b[/tex]

[tex]b=5[/tex]

Take point (2, 15) to compute the value of b.

Put [tex]x=2,y=15\ and\ m=5[/tex] in equation 1.

[tex]y=mx+b[/tex]

[tex]15=5(2)+b[/tex]

[tex]15=10+b[/tex]

[tex]15-10=b[/tex]

[tex]b=5[/tex]

So the equation of the line is.

[tex]y=mx+b[/tex]

Put m and b value in above equation.

[tex]y=5x+5[/tex]------------(2)

[tex]5x-y=-5[/tex]

add 10 both side in equation 2.

[tex]y+10=5x+5+10[/tex]

[tex]y+10=5x+15[/tex]

[tex]y+10=5(x+3)[/tex]

So the equation of line that passes through the point (2,15) and (0,5) is.

[tex]y=5x+5[/tex] or [tex]5x-y=-5[/tex] or [tex]y+10=5(x+3)[/tex]

Therefore, Neither the following equations represents a line that passes through the points  (2,15) and (0,5).

Option D

Step-by-step explanation:

when two points are given and we are asked to find the equation of a line passing through those points we use two-point form to arrive at the answer.

Let [tex]$(x_1,y_1)$[/tex] and [tex]$(x_2, y_2)$[/tex] be two points that passes through a line. Then the equation of the line is given by:

[tex]\frac{y - y_1}{y_2 - y_1} = \frac{x - x_1}{x_2 - x_1}[/tex]

Here [tex]$(x_1, y_1) = (-5, 10)$[/tex] and [tex]$(x_2,y_2) = (2, 8)$[/tex]

Therefore, [tex]\frac{y - 10}{-2} = \frac{x + 5}{7}[/tex]

[tex]$ \implies 7y - 70 = -2x - 10 $\\$ \implies 7y = - 2x + 60 $\\$ y = \frac{-2}{7}x + \frac{60}{7}[/tex]

The answer is the letter A

The equation of a straight line can be represented in the slope-intercept form, y = mx + c

Where c = y intercept

m represents the slope of the line.

m = (y2 - y1)/(x2 - x1)

y2 = final value of y

y 1 = initial value of y

x2 = final value of x

x1 = initial value of x

The line passes through (- 2, - 8) and (0, 2),

y2 = 2

y1 = - 8

x2 = 0

x1 = - 2

Slope,m = ( 2 - - 8)/(0 - - 2) = 10/2 = 5

To determine the y intercept, we would substitute x = 0, y = 2 and m = 5 into y = mx + c. It becomes

2 = 5 × 0 + c

2 = 0 + c

c = 2

c = - 8

The equation becomes

y = 5x + 2

The graph of the line would be y + 1 = m(x - 1) in which m is the slope. That slope would be the opposite and reciprocal of the one on the graph.

Step-by-step explanation:

To find the equation, start with the base form of point slope form and insert all known information.

y - y1 = m(x - x1)

y + 1 = m(x - 1)

answer is:

1.75 pounds

[tex]What the answers right answers only[/tex]

e) none of the above because the measure of angle cba is 101°

[tex]Find the measure of ∠cba. a) 25° b) 50° c) 75° d) 100° e) none of the above[/tex]

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