# Aline is perpendicular to another line m2= (-1/m1), where m1 is the slope of the original

###### Question:

## Answers

-3a+b=-3 => a=b+1 =>

12a+b=2 => 12(b+1)+b=2 => b = -10/13 => a=3/13

y=3/13x-10/13 - does not exist!

2 ONLY

Step-by-step explanation:

O

both are right

Step-by-step explanation:

okay so you already know that the y-intercept is 4 since a point is (0, 4)

but not to find the slope you can use the y2-y1/x2-x1

16 - 4/ -8 - 0 = 12/-8 = 3/-2

or

4 - 16/ 0 - (-8) = -12/8 = -3/2

it doesnt matter which you plug in first

so we know the slope (m) is -3/2 and the y-intercept (b) is 4, now to put it into an equation:

y = mx + b

y = -3/2x + 4

also im going to put this in slope-intercept form

3x + 2y = 8

-3x -3x

2y = -3x + 8

/2 /2

y = -3/2x + 4

y = -3/2x + 4 = y = -3/2x + 4

so both answers equal each other, meaning they both are right

First, find the slope of the line that goes through the 2 given points, which you should know how to do. Call it m. Then a perpendicular line must have a slope of -1/m. The slope-intercept form of the equation you seek is

y = (-1/m)x + b,

where b is any real number. Examine the list of choices, and pick any that have a slope of -1/m.

Hey there again!

First, let's find the slope of this line. We will divide the difference in the y's by the difference in the x's.

[tex]\frac{y}{x} =\frac{2+8}{0+2} =\frac{10}{2} = 5[/tex]

Our slope is 5, so our equation should look like this so far.

y=5x+b

But, the only answer that matches having a slope of 5 is B, so we don't even need to finish!

Therefore, our answer is B: y=5x+5

I hope this helps! Have a great day!

Option A is correct

A. Neither

Step-by-step explanation:

Given:

Two points are given (2, 15) and (0, 5)

Let [tex](x_{1}, y_{1})=(2,15)[/tex] and [tex](x_{2}, y_{2})=(0,5)[/tex]

The slope of the line [tex]m=\frac{y_{2}- y_{1}}{x_{2}- x_{1}}[/tex]

Put all known value in above equation.

[tex]m=\frac{5- 15}{0- 2}[/tex]

[tex]m=\frac{-10}{-2}[/tex]

[tex]m=5[/tex]

So the slope of the line [tex]m=5[/tex].

The equation of the is

[tex]y=mx+b[/tex] -------------------(1)

Where m is the slope of the line and b is y-intercept of the line.

Take point (0, 5) to compute the value of b.

Put [tex]x=0,y=5\ and\ m=5[/tex] in equation 1.

[tex]y=mx+b[/tex]

[tex]5=5(0)+b[/tex]

[tex]5=0+b[/tex]

[tex]b=5[/tex]

Take point (2, 15) to compute the value of b.

Put [tex]x=2,y=15\ and\ m=5[/tex] in equation 1.

[tex]y=mx+b[/tex]

[tex]15=5(2)+b[/tex]

[tex]15=10+b[/tex]

[tex]15-10=b[/tex]

[tex]b=5[/tex]

So the equation of the line is.

[tex]y=mx+b[/tex]

Put m and b value in above equation.

[tex]y=5x+5[/tex]------------(2)

[tex]5x-y=-5[/tex]

add 10 both side in equation 2.

[tex]y+10=5x+5+10[/tex]

[tex]y+10=5x+15[/tex]

[tex]y+10=5(x+3)[/tex]

So the equation of line that passes through the point (2,15) and (0,5) is.

[tex]y=5x+5[/tex] or [tex]5x-y=-5[/tex] or [tex]y+10=5(x+3)[/tex]

Therefore, Neither the following equations represents a line that passes through the points (2,15) and (0,5).

Option D

Step-by-step explanation:

when two points are given and we are asked to find the equation of a line passing through those points we use two-point form to arrive at the answer.

Let [tex]$(x_1,y_1)$[/tex] and [tex]$(x_2, y_2)$[/tex] be two points that passes through a line. Then the equation of the line is given by:

[tex]\frac{y - y_1}{y_2 - y_1} = \frac{x - x_1}{x_2 - x_1}[/tex]

Here [tex]$(x_1, y_1) = (-5, 10)$[/tex] and [tex]$(x_2,y_2) = (2, 8)$[/tex]

Therefore, [tex]\frac{y - 10}{-2} = \frac{x + 5}{7}[/tex]

[tex]$ \implies 7y - 70 = -2x - 10 $\\$ \implies 7y = - 2x + 60 $\\$ y = \frac{-2}{7}x + \frac{60}{7}[/tex]

The answer is the letter A

The equation of a straight line can be represented in the slope-intercept form, y = mx + c

Where c = y intercept

m represents the slope of the line.

m = (y2 - y1)/(x2 - x1)

y2 = final value of y

y 1 = initial value of y

x2 = final value of x

x1 = initial value of x

The line passes through (- 2, - 8) and (0, 2),

y2 = 2

y1 = - 8

x2 = 0

x1 = - 2

Slope,m = ( 2 - - 8)/(0 - - 2) = 10/2 = 5

To determine the y intercept, we would substitute x = 0, y = 2 and m = 5 into y = mx + c. It becomes

2 = 5 × 0 + c

2 = 0 + c

c = 2

c = - 8

The equation becomes

y = 5x + 2

The graph of the line would be y + 1 = m(x - 1) in which m is the slope. That slope would be the opposite and reciprocal of the one on the graph.

Step-by-step explanation:

To find the equation, start with the base form of point slope form and insert all known information.

y - y1 = m(x - x1)

y + 1 = m(x - 1)

answer is:

1.75 pounds

[tex]What the answers right answers only[/tex]e) none of the above because the measure of angle cba is 101°

[tex]Find the measure of ∠cba. a) 25° b) 50° c) 75° d) 100° e) none of the above[/tex]