Ahuman body contains 6 liters of blood. the hemoglobin content of blood is about 15.5g/100 ml of blood.

7 answers
Question:

Ahuman body contains 6 liters of blood. the hemoglobin content of blood is about 15.5g/100 ml of blood. the approximate hemoglobin molecular weight is 64,500g/mol. how many moles of hemoglobin are present

Answers

15,5g 100ml
Xg 6000 ml
X = 930g

64,5g 1 mol
930g X
X = 930/64,5 = 14,42 moles of hemoglobin

:•)

1. 12.6 moles

2. 8.95 moles

3.  2A + 5B → 3C

4. 48 moles

Explanation:

1. 2Fe + 3Cl₂ → 2FeCl₃

We assume the chlorine in excess. Ratio is 2:2

2 moles of Fe, can produce 2 moles of chloride

12.6 moles of Fe will produce 12.6 moles of chloride.

2. 2Fe + 3Cl₂ → 2FeCl₃

For the same reaction, first of all we need to convert the mass to moles:

500 g . 1mol / 55.85 g = 8.95 mol

As ratio is 2:2, the moles we have are the same, that the produced

4. The reaction for the combustion is:

2C₂H₆ (g) + 7O₂ (g) → 4CO₂ (g) + 6H₂O (l)

We assume the oxygen in excess.

Ratio is 2:6, so 2 mol of ethane produce 6 moles of water

Therefore 16 moles of ethane may produce (16 .6) / 2 = 48 moles

1. D (24.0 moles CO2)

2. A (.239 moles H2)

Explanation:

1. First Balance the equation

1 C3H8 + 5 O2 ---> 3 CO2 + 4 H2O

Then set up a stoiciometric equation so that the moles of O2 cancel out

40mol O2 x [tex]\frac{3 mole CO2}{5 mole O2}[/tex] = 24.0 moles CO2

2. Set up a stoichiometric equation

10 grams Fe x [tex]\frac{1 mole Fe}{55.85 grams Fe}[/tex] x [tex]\frac{4 mole H2}{3 mole Fe}[/tex] = 0.239 moles H2

1. The molarity of the stock solution of luminol = 1,431 M

2. 0.12 moles of luminol is present in 2.00 L of the diluted spray

3. The volume of the stock solution (Part A) would contain the number of moles present in the diluted solution (Part B): 83.86 ml

Further explanation

Stoichiometry in Chemistry studies about chemical reactions mainly emphasizing quantitative, such as the calculation of volume, mass, amount, which is related to the number of ions, molecules, elements, etc.

In stoichiometry included :

1. Relative atomic mass2. Relative molecular mass

is the relative atomic mass of the molecule

3. mole

1 mole is the number of particles contained in a substance with the same number of atoms in 12 gr C-12

1 mole = 6.02.10²³ particles

While the number of moles can also be obtained by dividing the mass (in grams) by the relative mass of the element or the relative mass of the molecule

[tex]\large{\boxed{\bold{mol\:=\:\frac{grams}{ relative\:mass} }}}[/tex]

Luminol (C₈H₇N₃O₂) is a substance used to detect traces of blood in the scene of a crime because it reacts with iron in the blood

a. a luminol stock solution by adding 19.0g of luminol into a total volume of 75.0mL of H2O.

So the molarity is

1. Luminol mole

- the relative molecular mass of Luminol

= 8. C + 7.H + 3.N + 2.16

= 8.12 + 7.1 + 3.14 + 2.16

= 177 grams / mol

so the mole:

mol = gram / relative molecular mass

[tex]mole=\frac{19}{177}[/tex]

mole = 0.1073

2. Molarity (M)

M = mole / volume

[tex]M\:=\:{\frac{ 0.1703 }{75.10^{-3} L}[/tex]

M = 1,431

b. luminol concentration in a spray bottle 6.00 × 10⁻² M. So that in 2 L of solution, the number of moles is:

mole = M x volume

mole = 6.10⁻² x 2

mole = 0.12

c. Molarity of the stock solution (Part A) = 1,431 M

the number of moles present in the diluted solution (Part B) = 0.12

So the volume of the stock solution (Part A) would contain the number of moles present in the diluted solution (Part B) is:

volume = mol / M

[tex]volume\:=\:\frac{0.12}{1.431}[/tex]

volume = 0.08386 L = 83.86 ml

Learn more

moles of water you can produce

the number of each atom present in the compound's formula

the ratio of hydrogen atoms (H) to oxygen atoms (O) in 2 l of water

Keywords: mole, volume, molarity, Luminol, the relative molecular mass


[tex]On part c: the forensic technician at a crime scene has just prepared a luminol stock solution by[/tex]

Here is the

Explanation:


[tex]How many moles are present in 10.0g aspartame[/tex]

I didn't solve part a) because you said in the statement that you needed only the answer from part c), therefore the answer equals:

n = 0.120 moles

V = 83.9 mL

Explanation:

The dilution of a 1.43 M to 0.06 M solution is 22.8 to 1 relative. Therefore, 22.8 parts of water must be added to the original solution. The amount of moles is calculated as follows:

n = M * V = 2 L * 0.06 M = 0.120 moles

The volume is calculated as follows:

V = n/M = 0.120 moles/1.43 M = 83.9 mL

Did i just say moles i’m sorry but heat kinda question is this

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