Afirehouse pantry has 52 cans of vegetables and 74 cans of soup. each shelf holds 9 cans. what is the least number of shelves

4 answers
Question:

Afirehouse pantry has 52 cans of vegetables and 74 cans of soup. each shelf holds 9 cans. what is the least number of shelves needed for all the cans? what if 18 cans fit on a shelf what is the the least number of shelves needed? describe how your answer would be different.

Answers

Part 1: 14 because 52+ 74 equals 126 divided by 9 equals 14

part 2:7 because 52+ 74 equals 126 divided by 18 equals 7. 

The first question's answer is 14. 74 + 52= 126  126 ÷ 9= 14.

The second question's answer is 7. 74 + 52= 126  126 ÷18= 7.

  5.   y=6; de=7; fg=8

  6.   x=4.2; jl=14.2; mn=13

step-by-step explanation:

when chords cross inside a circle, the product of the segment lengths is a constant.

5. dh×eh = fh×gh

  y = gh = dh×eh/fh = 3×4/2 . . . divide by the coefficient of gh

  y = 6

of course, the total chord length is the sum of the lengths of its segments.

  de = dh +eh = 3+4 = 7

  fg = fh +gh = 2+6 = 8

6. this problem works the same way as the previous one.

  x = lk = mk×nk/jk = 6×7/10 = 4.2

  jl = jk +lk = 10 +4.2 = 14.2

  mn = mk +nk = 6 +7 = 13

comment on chords and secants

you can think of the points h (problem 5) and k (problem 6) as points where the chords meet. a chord is part of a secant line, a line that intersects the circle in two points. one can also consider these points (h or k) to be the points where the respective secant lines meet.

then, the product that is a constant is the product of the distance from the meeting point (h or k) to one circle intersection with the distance from that meeting point to the other circle intersection. for problem 5, the constant is the product hd×he = hf×hg.

it turns out that this rule regarding the products of lengths to points of intersection is also true when the secants intersect outside the circle.

that is, you only need to remember one rule to work both kinds of problems.

[tex]Find the value of the variable and the length of each chord for #5 and #6.[/tex]

answer: the answer is 40.82

step-by-step explanation: 3.14 x 13(or half of 26) to the power of 2

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