Aclydesdale drinks about 120 gallons of water every 4 days. at this rate, about how many gallons of

10 answers
Question:

Aclydesdale drinks about 120 gallons of water every 4 days. at this rate, about how many gallons of water does a clydesdale drink in 28 day?

Answers

The answer to your question is 840 gallons in 28 days.

120 gallon x 7
4 days x7
840 gallon in 28 days

120 gallons in 4 days120/4 = 30 gallons per day

for 28 days...
30 * 28 = 840 gallons <==

Now go to school...lol

25 drinks per minutes

840 gallons is the correct answer 

840 gallons, 28/4=6 6*120=840

840. 120 divided by 4 is 30. 30x28=840.

840 gallons.

Clydesdale drinks a total of 840 gallons in 28 days

Step-by-step explanation:

Step 1: Calculate rate at which water is drank

The expression for the total amount of water drank is;

Total amount of water=quantity drank per day×number of days

where;

quantity drank per day=g

number of days=4 days

total amount of water drank=120 gallons

replacing;

120=(g×4)

4 g=120

g=120/4

g=30

Quantity drank per day=30 gallons per day

Step 2: Total amount he drinks in 28 days

Using the expression;

Total amount of water=quantity drank per day×number of days

where;

quantity drank per day=30 gallons per day

number of days=28 days

replacing;

Total amount of water=(30×28)=840 gallons

Clydesdale drinks a total of 840 gallons in 28 days

A clydes dale can drink up to 840 gallons of water in 28 days

A clydesdale would drink about 840 gallons in 28 days time.
120/4 = 30 (gallons a day) x 28 (days time) = about 840

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