Acheetah, mass m, is initially at rest at time t=0. after spotting prey, it begins to run straight toward

a. [tex]v=\sqrt{ \frac{2P\times t}{m}}[/tex]

b. The magnitude of the force supplied by the cheetah's legs greater right after t=0

Explanation:

We know:

Kinetic Energy

[tex]K.E.= \frac{1}{2} m.v^2[/tex]

where:

m= mass of the body

v= velocity of the body

also,

Power, P= rate of energy or work.

So, if the Cheetah's leg produce power P for time t then the kinetic energy of the Cheetah will be given as:

[tex]K.E.= P\times t[/tex]

[tex]\Rightarrow \frac{1}{2}m.v^2=P\times t[/tex]

[tex]v=\sqrt{ \frac{2P\times t}{m}}[/tex]

The magnitude of the force produced by the legs of the cheetah is greater just after time t=0 because it has spent a fraction of second using its energy.

answer: (431,2)

step-by-step explanation:

the simple machine has three main features. they are:

fulcrum is the center point or pivot point of the machine. effort is input force/ applied force. load is external force/ output.

the keisha 's machine labels are

x : load

y: fulcrum

z: lever