# Ablock of copper of unknown mass has an initial temperature of 65.4 ∘c. the copper

###### Question:

## Answers

37.840g

Explanation:

We have to use this equation:

Q=m*c*ΔT

Q= Symbol of heat transfer

ΔT= Change in temperature

c = specific heat.

First, we calculate the amount of heat transferred to water from copper:

m = 95.7g

c = 4.1813 J/gºC (It's a known value)

ΔT = 24.2ºC - 22.7ºC = 1.5

Q = (95.7g)(4.1813J/gºC)(1.5ºC)

Q = 600.226J This is the heat absorbed by water which is the same released by copper

So Q water = - Q copper

Now we can calculate the mass of copper like this:

Q = - 600.226J

c = 0.385J/gºC

ΔT = (24.2ºC - 65.4ºC) = -41.2ºC

m = ?

we solve for m in the equation Q=m*c*ΔT and we find:

[tex]\frac{Q}{c ΔT} = m[/tex]

[tex]\frac{-600.226J}{(0.385J/gºC) (- 41ºC)} = 37.840g[/tex]

The mass of the copper block: 37,829 g

Further explanationThe law of conservation of energy can be applied to heat changes, i.e. the heat received / absorbed is the same as the heat released

Q in = Q outHeat can be calculated using the formula:

[tex]\rm \large{\boxed{\bold{Q=m\times c\times \Delta T}}}[/tex]

Q = heat, J

m = mass, g

c = specific heat, joules / g ° C

∆T = temperature difference, ° C / K

1. H₂Om = 95.7 g

c = 4.18 J / gºC

delta T = 24.2 °C - 22.7 °C = 1.5 °C

Q H₂O = 95.7 x 4.18 x 1.5

Q H₂O = 600,039 J

2. Cuc = 0.385 J / gºC

delta T = 65.4 °C - 24.2 °C = 41.2 °C

QH₂O = Q Cu

600,039 J = m. 0.385 J / gºC. 41.2. °C

[tex]\rm m=\dfrac{600.039}{0.385\times 41.2}\\\\m=\boxed{37.829\:g}}[/tex]

Learn morethe difference between temperature and heat

Specific heat

relationships among temperature, heat, and thermal energy.

When heat is added to a substance

false

explanation:

boats, things on boats luggage are way more heavy then water.

Awoodchuck would chuck all the wood he could chuck if a woodchuck could chuck wood.