A transformation of ΔSTV results in ΔUTV. Which transformation maps the pre-image to the image?

6 answers
Question:

A transformation of ΔSTV results in ΔUTV. Which transformation maps the pre-image to the image?

Answers

Notice that TV is in the original triangle and in the image. That means that we are looking for a transformation where this segment remains fixed (doesn’t move) which is the case when doing a reflection. A reflection over the line segment TV would leave that segment unchanged. Think of having the triangle iba page and picking p vertex S swinging it over TV and having it land on the other side. TV the line of reflection remains fixed while S moves to a new point here called U.

answer: it is a reflection across the line tv.

explanation:   since, in a reflection we flip an object across a line without changing its size or shape.

here, results in in which,

st=ut (given)

sv= uv (given)

and, tv=tv (common segment)

therefore, by sss postulate,

thus, there is no change in shape or size of the given triangle stv.

hence,   is reflected to across the line tv.

Is there any way that you could add a picture of the the image and the pre image look like so that I have more information to help you with?

Notice that tv is in the original triangle and in the image. that means that we are looking for a transformation where this segment remains fixed (doesn’t move) which is the case when doing a reflection. a reflection over the line segment tv would leave that segment unchanged. think of having the triangle iba page and picking p vertex s swinging it over tv and having it land on the other side. tv the line of reflection remains fixed while s moves to a new point here called u.

Stv was mirrored to create utv

reflection on ed 2020

Explanation:

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