A solid cylinder of diameter 100 mm and height 50 mm is forged between two frictionless flat dies to a height of 25 mm.
3 answers
Question:
A solid cylinder of diameter 100 mm and height 50 mm is forged between two frictionless flat dies to a height of 25 mm. What is the percentage change in diameter? a. 0
b. 2.07
c. 20.7
d. 41.4
b. 2.07
c. 20.7
d. 41.4
Answers
d. 41.4
Explanation:
The initial diameter di = 100mm
The initial height hi {✓59m
Final height = 25 m
Final diameter = ?
Initial volume = after forging volume
D*(di)²*hi = D *(df)²*hf
D will cancel out from either sides of the equation
100² x 50 = df²x25
10000x2 = df²
20000 = df²
df = √20000
df = 141.42mm
Change in diameter = 141.42-100
= 41.42
The percentage change = 41.42/100*100
= 41.4%
The last option is the answer
1
explanation:
answer:
a
explanation:
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