A line contains points M(1, 3) and N(5, 0). What is the slope of MN? negative StartFraction 4 Over 3

-3/4 or it could also be -0.75

the slope is -3/4

3/4

Step-by-step explanation:

[tex]-\dfrac{3}{4}[/tex]

Step-by-step explanation:

[tex]slope = m = \dfrac{y_2 - y_1}{x_2 - x_1}[/tex]

[tex]m = \dfrac{0 - 3}{5 - 1}[/tex]

[tex]m = \dfrac{-3}{4}[/tex]

[tex]m = -\dfrac{3}{4}[/tex]

A

Step-by-step explanation:

The definition of slope in Wikipedia:

Slope is calculated by finding the ratio of the "vertical change" to the "horizontal change" between (any) two distinct points on a line

Therefore, slope of MN is [tex]\frac{1-5}{(3-0)} =-\frac{4}{3}[/tex]

For this case we have the following points:

 M (1,3)

 N (5.0)

 The slope of the line is given by:

 m = (y2-y1) / (x2-x1)

 Substituting values we have:

 m = (0-3) / (5-1)

 Rewriting we have:

 m = -3 / 4

 The slope of the line is:

 m = -3 / 4

option B

Step-by-step explanation:

B. Use the formula m=(Y2-Y1)/(X2-X1). For this problem it would be (0-3)/(5-1)= -3/4.

For this case we have the following points:
 M (1,3)
 N (5.0)
 The slope of the line is given by:
 m = (y2-y1) / (x2-x1)
 Substituting values we have:
 m = (0-3) / (5-1)
 Rewriting we have:
 m = -3 / 4
 
 The slope of the line is:
 m = -3 / 4

Slope of a line passing through the points (x₁,y₁) and (x₂,y₂).
m=(y₂-y₁)/(x₂-x₁)

Data: We have the points:
M(1,3)
N(5,0)

m=(0-3)/(5-1)=-3/4

the slope is -3/4