A container in the shape of a cube will be completely filled with sand. The container has an edge length of 8 inches. What is

8 to the exponent of 3

You could fit 5.25 cubic inches inside the prism.

Step-by-step explanation:

Hi, to answer this question we have to calculate the volume of the rectangular prism:

Volume (V) = Length x width x height

Replacing with the values given:

V = 1.75 in x 2 in x 1.5 in  

Solving for V:

V = 5.25 cubic inches

You could fit 5.25 cubic inches inside the prism.

Feel free to ask for more if needed or if you did not understand something.

216 cubic inches

Step-by-step explanation:

We want to simplify:

102 * 4 - 3(8 * 8 * 1)

We will apply BODMAS:

Solving the Bracket first:

102 * 4 - 3(64)

102 * 4 - 192

=> 408 - 192

= 216 cubic inches

He will need 216 cubic inches of packing foam.

In inches, the radius of the can is 2.

Step-by-step explanation:

Given:

The number of cubic inches in the volume of a 6-inch high cylindrical can equals the number of square inches in the area of the label that covers the lateral surface of the can.

Now, to find the radius of the can in inches.

Let the radius of can be [tex]r.[/tex]

Height of can = [tex]6\ inches.[/tex]

As given, the number of cubic inches of the volume of the cylindrical can equals the number of square inches in the area of the label that covers the lateral surface of the can.

So,

Volume of can = lateral surface area of can.

Now, we put formula of volume and lateral surface area of cylinder:

[tex]\pi r^2h=2\pi rh[/tex]

[tex]\pi \times r\times r\times 6=2\times \pi \times r\times 6[/tex]

Dividing both sides by [tex]\pi \times r[/tex] we get:

[tex]r\times 6=2\times 6[/tex]

[tex]6r=12[/tex]

Dividing both sides by 6 we get:

[tex]r=2.[/tex]

Therefore, in inches, the radius of the can is 2.

The amount of cubic inches would be 1728cubic inches for every cubic foot.

You could fit 5.25 cubic inches inside the prism.

Step-by-step explanation:

In order to calculate the number of cubic inches that could fit in the prism we first need to calculate it's volume, this is given by the formula below:

volume = length*width*height

Applying the data from the question:

volume = 1.75*1.5*2

volume = 5.25 inches³

Thefore you could fit 5.25 cubic inches inside the prism.

B is the answer

the formula is :

[tex]s = \pi {r}^{2} h[/tex]
which r stands for radius
and h stands for height

the diameter is 16
so the radius is
[tex]16 \div 2 = 8[/tex]

hope you understand it

Its about 3.14 * 2.5^2 * 13.5    ( using formula V = pi r^2 h)

=  265 in^3 to nearest in^3.

Let r = radius of the hard rubber ball.

Because the circumference of the ball is 13 inches, therefore
2πr = 13
r = 13/(2π) = 2.069 in

In order to fit the ball into a cube-shaped box with integer dimensions, each side of the box should measure 3 inches (the next integer greater than 2.069).

The volume of the cube-shaped box is 3³ = 27 in³.

The volume is 27 in³.

Let r =  radius of the hard rubber ball.
The circumference of the ball is 13 inches, therefore
2πr = 13
r = 13/(2π) = 2.069 inches
The diameter of the ball is 2*2.069 = 4.138 inches.

The ball is hard and cannot be compressed. Therefore the length of a side of the smallest cube-shaped box with integer dimensions is 5 inches.
The volume of the box is 5³ = 125 in³.

125 in³