# A bag contains 10 red marbles, 15 yellow marbles, 5 green marbles, and 20 blue marbles. Two marbles are drawn from the bag. Which

###### Question:

bag.

Which expression represents the probability that one of the marbles is red and the other is blue?

O 60616051)

0

50C2

(021)(20P1)

50P2

## Answers

It is the third option: (10C1) (20C1( / 50C2.

Step-by-step explanation:

The number of ways of selecting 2 marbles = the number of combination of any 2 marbles in the 50 marbles in the bag and this is 50C2. It is combinations because the order of drawing the marbles does not matter.

The number of combinations of one being red and the other blue = 10C1 times 20C1.

So the answer is (10C1) (20C1( / 50C2.

its C

Step-by-step explanation:

The answer on ED is C

Step-by-step explanation:

The expression could be P(R and B) =P(R)*P(B) where two events are independent

The probability will be 4/25

Step-by-step explanation:

You can use the tree diagram to visualize the chances where red and blue marble appear when two marbles are drawn

Given;

Red marbles=10Yellow marbles=15Green marbles=5Blue marbles=20P(S)=10+15+5+20=50

Probability of drawing a red , P(R)=10/50

Probability of drawing a blue; P(B)=20/50

From the tree diagram you will notice the probability of drawing a red then a blue occurs at RB and BR

In the first occurrence , RB the probability will be

[tex]\frac{10}{50} *\frac{20}{50} =\frac{200}{2500}[/tex]

In the second occurrence, BR the probability will be

[tex]\frac{20}{50} *\frac{10}{50} =\frac{200}{2500}[/tex]

Add the two probabilities

[tex]\frac{200}{2500} +\frac{200}{2500} =\frac{400}{2500} =\frac{4}{25}[/tex]

We are dealing with combinations here not permuatations because the order of picking does not matter.

so its the produce of 1 from 10 red * 1 from 20 blue, divided by 2 combinations FROM 50

Choice 3 is the correct one.

(₁₀C₁) × (₂₀C₁)

₅₀C₂

Explanation:

There are a total number of 10 + 15 + 5 + 20 = 50 marbles.

The number of ways in which any two marbles can be drawn is the combination of 50 marbles taken two at a time: ₅₀C₂, since the order does not matter.

There are 10 red marbles and 20 blue marbles.

Thus, the combinations with one red marble are: ₁₀C₁.

The combinations with one blue marble are: ₂₀C₁.

The combinations with one red and one blue marble is the product of the previous two:

₁₀C₁ × ₂₀C₁Thus, the probability that one of the marbles is read and the other is blue is the quotient of the two sets:

(₁₀C₁) × (₂₀C₁)₅₀C₂