A 10 kilogram painting hangs from two symmetric wires that have an angle of100° between them. Gravity will exert a force of 98 Newtons

4 answers
Question:

A 10 kilogram painting hangs from two symmetric wires that have an angle of 100° between them. Gravity will exert a force of 98 Newtons on 10 kilograms.
What is the magnitude of the force on each wire needed to keep the painting
in equilibrium?
Hint: Each wire has a vertical component which is half the force needed to
balance the force of gravity.
Magnitude:
N

Answers

[tex]a_{15}[/tex] = 5

step-by-step explanation:

to find the 15th term substitute n = 15 into the nth term formula

[tex]a_{15}[/tex] = (- 3 × 15 ) + 50 = - 45 + 50 = 5

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