9. Calculate the area of the pentagon in the figure below.
Question:
[tex]9. Calculate the area of the pentagon in the figure below.[/tex]
Answers
1) 76.5 cm²
2) 35.07 m²
Step-by-step explanation:
1) The area of a trapezoid is A = (B + b)h/2
A = (11.5+6.5).8.5/2 = 18 . 8.5/2 = 153/2 = 76.5 cm²
2) For the pentagon, as it is a regular pentagon, we can divide it into 2 shapes. A equilateral triangle and a square.
Area of the square = l² = 9² = 81 m²
Area of a equilateral trinagle = l²√3/4 = 9²√3/4 = 81√3/42 = 81 . 1.73/2 = 140.3/4 = 35.07 m²
132.5 cm²
Step-by-step explanation:
Given the ratio of 2 similar figures = a : b, then the
ratio of areas = a² : b²
Here the ratio of sides = 5 : 9, thus
ratio of areas = 5² : 9² = 25 : 81
Let x be the area of the smaller pentagon then by proportion
[tex]\frac{x}{25}[/tex] = [tex]\frac{429.3}{81}[/tex] ( cross- multiply )
81x = 10732.5 ( divide both sides by 81 )
x = 132.5
Area of smaller pentagon is 132.5 cm²
139 cm squared
The area of a trapezoid is given by
... A = (1/2)(b1 +b2)h
... A = (1/2)(11.5 +6.5)·(8.5) = 76.5 ≈ 77
The area of BEAR is about 77 cm².
The conventional formula for the area of a regular polygon makes use of its perimeter and the length of the apothem. For an n-sided polygon with side length s, the perimeter is p = n·s. The length of the apothem is found using trigonometry to be a = (s/2)/tan(180°/n). Then the area is ...
... A = (1/2)ap
... A = (1/2)(s/(2tan(180°/n)))(ns)
... A = (n/4)s²/tan(180°/n)
We have a polygon with s=9 and n=5, so its area is
... A = (5/4)·9²/tan(36°) ≈ 139.36
The area of PENTA is about 139 m².
Given
1) Trapezoid BEAR with bases 11.5 and 6.5 and height 8.5, all in cm.
2) Regular pentagon PENTA with side lengths 9 m
FindThe area of each figure, rounded to the nearest integer
Solution1) The area of a trapezoid is given by
... A = (1/2)(b1 +b2)h
... A = (1/2)(11.5 +6.5)·(8.5) = 76.5 ≈ 77
The area of BEAR is about 77 cm².
2) The conventional formula for the area of a regular polygon makes use of its perimeter and the length of the apothem. For an n-sided polygon with side length s, the perimeter is p = n·s. The length of the apothem is found using trigonometry to be a = (s/2)/tan(180°/n). Then the area is ...
... A = (1/2)ap
... A = (1/2)(s/(2tan(180°/n)))(ns)
... A = (n/4)s²/tan(180°/n)
We have a polygon with s=9 and n=5, so its area is
... A = (5/4)·9²/tan(36°) ≈ 139.36
The area of PENTA is about 139 m².
The are the area should be 86
Y=3x+1 so the first one
[tex]Me answer this question question 2) select the function that matches the graph[/tex]
+1,000)=g7e=mc2-g=7 because if you know algebra you should know g=7 to get your answer